# Plus Two Math's Solution Miscellaneous Chapter2 Inverse Trigonometric Functions

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 Board SCERT, Kerala Text Book NCERT Based Class Plus Two Subject Math's Textbook Solution Chapter Chapter 2 Exercise Miscellaneous Exercise Chapter Name Inverse Trigonometric Functions Category Plus Two Kerala

## Kerala Syllabus Plus Two Math's Textbook Solution Chapter  2 Inverse Trigonometric Functions Miscellaneous Exercise

### Chapter  2  Inverse Trigonometric Functions Solution

Kerala plus two maths NCERT textbooks, we provide complete solutions for the exercise and answers provided at the end of each chapter. We also cover the entire syllabus given by the Board of secondary education, Kerala state.

### Chapter  2  Inverse Trigonometric Functions Miscellaneous Exercise

Prove Consider, Prove L.H.S = Prove test

Prove  Now, we have: Prove  Using (1) and (2), we have Solve is equal to

(A) (B) (C) (D) #### Hence option D

Solve is equal to

(A) (B). (C) (D)  Hence, the correct answer is C.

Find the value of We know that cos−1 (cos x) = x if , which is the principal value branch of cos −1x.

Here, Now, can be written as: Find the value of We know that tan−1 (tan x) = x if , which is the principal value branch of tan −1x.

Here, Now, can be written as:  Prove  Now, we have: Prove  Now, we have: Prove  Now, we will prove that: Prove Let  Then, Prove [Hint: putx = cos 2θ]

Put  so that , then we have Solve   Solve  Solve then x is equal to

(A) (B) (C) 0 (D)  Therefore, from equation (1), we have Put x = sin y. Then, we have: But, when , it can be observed that:  is not the solution of the given equation.

Thus, x = 0.

Hence, the correct answer is C.

#### Chapter 2: Inverse Trigonometric Functions Miscellaneous Exercise Solution- Preview

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