Plus Two Math's Solution Miscellaneous Chapter2 Inverse Trigonometric Functions

Inverse trigonometry as its name indicates study materials, with inverse trigonometry pdf questions, you can use the inverse trigonometry pdf to do the inverse trigonometry book test, inverse trigonometry notes, and other miscellaneous questions of inverse trigonometry. Proposing a simple technique to solve complex math problems is not an easy task. It requires good knowledge, understanding, and a thorough explanation. This is where the book takes over! Inverse Trigonometry, Math Study Materials is a very important topic in maths for all competitive exams. In this study materials, I have tried to solve all basic questions in inverse trigonometry.

Board	SCERT, Kerala
Text Book	NCERT Based
Class	Plus Two
Subject	Math's Textbook Solution
Chapter	Chapter 2
Exercise	Miscellaneous Exercise
Chapter Name	Inverse Trigonometric Functions
Category	Plus Two Kerala

Kerala Syllabus Plus Two Math's Textbook Solution Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise

Chapter 2 Inverse Trigonometric Functions Solution

Kerala plus two maths NCERT textbooks, we provide complete solutions for the exercise and answers provided at the end of each chapter. We also cover the entire syllabus given by the Board of secondary education, Kerala state.

Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise

Question 1:

Prove

Solution 1:

Consider, $\left ( \frac{\sqrt{1+sinx}+\sqrt{1-sinx} }{\sqrt{1+sinx}-\sqrt{1-sinx}} \right )$

Question 2:

Prove

Solution 2:

L.H.S = $tan^{-1}\frac{1}{5}+tan^{-1}\frac{1}{7}+tan^{-1}\frac{1}{3}+tan^{-1}\frac{1}{8}$

Question 3:

Prove

Solution 3:

test

Question 4:

Prove

Solution 4:

Now, we have:

Question 5:

Prove

Solution 5:

Using (1) and (2), we have

Question 6:

Solveis equal to

(A) (B) (C) (D)

Solution 6:

sin $\left ( tan^{-1} (x)\right )=sin\theta$

$\theta =tan^{-1}(x)$

$tan^{-1}(x)=\theta$

$tan(\theta )=x$

$\therefore sin\left ( tan^{-1}(x) \right )=\frac{x}{1+x^{2}}$

Hence option D

Question 7:

Solveis equal to

(A) (B). (C) (D)

Solution 7:

Hence, the correct answer is C.

Question 8:

Find the value of

Solution 8:

We know that cos⁻¹ (cos x) = x if, which is the principal value branch of cos ⁻¹x.

Here,

Now, can be written as:

Question 9:

Find the value of

Solution 9:

We know that tan⁻¹ (tan x) = x if, which is the principal value branch of tan ⁻¹x.

Here,

Now, can be written as:

Question 10:

Prove

Solution 10:

Now, we have:

Question 11:

Prove

Solution 11:

Now, we have:

Question 12:

Prove

Solution 12:

Now, we will prove that:

Question 13:

Prove

Solution 13:

Let $x=tan^{2}\theta$ Then, $\sqrt{x}=tan\theta$

$\Rightarrow \theta =tan^{-1}\sqrt{x}$

Question 14:

Prove [Hint: putx = cos 2θ]

Solution 14:

Put $x=cos2\Theta$ so that $\theta =\frac{1}{2}cos^{-1}x$ , then we have

Question 15:

Solve

Solution 15:

Question 16:

Solve

Solution 16:

Question 17:

Solve, then x is equal to

(A) (B) (C) 0 (D)

Solution 17:

Therefore, from equation (1), we have

Put x = sin y. Then, we have:

But, when, it can be observed that:

is not the solution of the given equation.

Thus, x = 0.

Hence, the correct answer is C.

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Chapter 2: Inverse Trigonometric Functions Miscellaneous Exercise Solution

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Plus Two Math's Chapter Wise Textbook Solution PDF Download

Plus Two Math's Part I

Chapter 1: Relations and Functions
Chapter 2: Inverse Trigonometric Functions
Chapter 3: Matrices
Chapter 4: Determinants
Chapter 5: Continuity and Differentiability
Chapter 6: Application of Derivatives

Plus Two Math's Part II

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Plus Two Math's Solution Miscellaneous Chapter2 Inverse Trigonometric Functions

Kerala Syllabus Plus Two Math's Textbook Solution Chapter 2 Inverse Trigonometric Functions Miscellaneous Exercise

Chapter 2 Inverse Trigonometric Functions Solution